2. Write the mixed repeating (recurring) decimal number as a proper fraction.
0.2917 can be written as a proper fraction.
- The numerator is smaller than the denominator.
Set up the first equation.
- Let y equal the decimal number:
y = 0.2917
Set up the second equation.
- Number of decimal places repeating: 1
Multiply both sides of the first equation by 101 = 10
y = 0.2917
10 × y = 10 × 0.2917
10 × y = 2.917
Get the same number of decimal places as for y:
10 × y = 2.9177
Note: 2.9177 = 2.917
Subtract the first equation from the second one.
- Having the same number of decimal places ...
- The repeating pattern drops off by subtracting the two equations.
10 × y - y = 2.9177 - 0.2917 ⇒
(10 - 1) × y = 2.9177 - 0.2917 ⇒
We now have a new equation:
9 × y = 2.626
Solve for y in the new equation.
9 × y = 2.626 ⇒
y = 2.626/9
Let the result written as a fraction.
Now we can write the number as a fraction.
According to our first equation:
y = 0.2917
According to our calculations:
y = 2.626/9
⇒ 0.2917 = 2.626/9
Get rid of the decimal places in the fraction above.
- Multiply the top and the bottom number by 1,000.
- 1 followed by as many 0-s as the number of digits after the decimal point.
0.2917 = (2.626 × 1,000)/(9 × 1,000)
0.2917 = 2,626/9,000
3. Reduce (simplify) the fraction above:
2,626/9,000
to the lowest terms, to its simplest equivalent form, irreducible.
To reduce a fraction to the lowest terms divide the numerator and denominator by their greatest (highest) common factor (divisor), GCF.
Factor the numerator and denominator (prime factorization).
2,626 = 2 × 13 × 101
9,000 = 23 × 32 × 53
Calculate the greatest (highest) common factor (divisor), GCF.
Multiply all the common prime factors by the lowest exponents.
GCF (2 × 13 × 101; 23 × 32 × 53) = 2
Divide both the numerator and the denominator by their GCF.
2,626/9,000 =
(2 × 13 × 101)/(23 × 32 × 53) =
((2 × 13 × 101) ÷ 2) / ((23 × 32 × 53) ÷ 2) =
(13 × 101)/(22 × 32 × 53) =
1,313/4,500