2. Write the mixed repeating (recurring) decimal number as a proper fraction.
0.39 can be written as a proper fraction.
- The numerator is smaller than the denominator.
Set up the first equation.
- Let y equal the decimal number:
y = 0.39
Set up the second equation.
- Number of decimal places repeating: 1
Multiply both sides of the first equation by 101 = 10
y = 0.39
10 × y = 10 × 0.39
10 × y = 3.9
Get the same number of decimal places as for y:
10 × y = 3.99
Note: 3.99 = 3.9
Subtract the first equation from the second one.
- Having the same number of decimal places ...
- The repeating pattern drops off by subtracting the two equations.
10 × y - y = 3.99 - 0.39 ⇒
(10 - 1) × y = 3.99 - 0.39 ⇒
We now have a new equation:
9 × y = 3.6
Solve for y in the new equation.
9 × y = 3.6 ⇒
y = 3.6/9
Let the result written as a fraction.
Now we can write the number as a fraction.
According to our first equation:
y = 0.39
According to our calculations:
y = 3.6/9
⇒ 0.39 = 3.6/9
Get rid of the decimal places in the fraction above.
- Multiply the top and the bottom number by 10.
- 1 followed by as many 0-s as the number of digits after the decimal point.
0.39 = (3.6 × 10)/(9 × 10)
0.39 = 36/90
3. Reduce (simplify) the fraction above:
36/90
to the lowest terms, to its simplest equivalent form, irreducible.
To reduce a fraction to the lowest terms divide the numerator and denominator by their greatest (highest) common factor (divisor), GCF.
Factor the numerator and denominator (prime factorization).
36 = 22 × 32
90 = 2 × 32 × 5
Calculate the greatest (highest) common factor (divisor), GCF.
Multiply all the common prime factors by the lowest exponents.
GCF (22 × 32; 2 × 32 × 5) = 2 × 32
Divide both the numerator and the denominator by their GCF.
36/90 =
(22 × 32)/(2 × 32 × 5) =
((22 × 32) ÷ (2 × 32)) / ((2 × 32 × 5) ÷ (2 × 32)) =
2/5