2. Write the mixed repeating (recurring) decimal number as a proper fraction.
0.4548 can be written as a proper fraction.
- The numerator is smaller than the denominator.
Set up the first equation.
- Let y equal the decimal number:
y = 0.4548
Set up the second equation.
- Number of decimal places repeating: 1
Multiply both sides of the first equation by 101 = 10
y = 0.4548
10 × y = 10 × 0.4548
10 × y = 4.548
Get the same number of decimal places as for y:
10 × y = 4.5488
Note: 4.5488 = 4.548
Subtract the first equation from the second one.
- Having the same number of decimal places ...
- The repeating pattern drops off by subtracting the two equations.
10 × y - y = 4.5488 - 0.4548 ⇒
(10 - 1) × y = 4.5488 - 0.4548 ⇒
We now have a new equation:
9 × y = 4.094
Solve for y in the new equation.
9 × y = 4.094 ⇒
y = 4.094/9
Let the result written as a fraction.
Now we can write the number as a fraction.
According to our first equation:
y = 0.4548
According to our calculations:
y = 4.094/9
⇒ 0.4548 = 4.094/9
Get rid of the decimal places in the fraction above.
- Multiply the top and the bottom number by 1,000.
- 1 followed by as many 0-s as the number of digits after the decimal point.
0.4548 = (4.094 × 1,000)/(9 × 1,000)
0.4548 = 4,094/9,000
3. Reduce (simplify) the fraction above:
4,094/9,000
to the lowest terms, to its simplest equivalent form, irreducible.
To reduce a fraction to the lowest terms divide the numerator and denominator by their greatest (highest) common factor (divisor), GCF.
Factor the numerator and denominator (prime factorization).
4,094 = 2 × 23 × 89
9,000 = 23 × 32 × 53
Calculate the greatest (highest) common factor (divisor), GCF.
Multiply all the common prime factors by the lowest exponents.
GCF (2 × 23 × 89; 23 × 32 × 53) = 2
Divide both the numerator and the denominator by their GCF.
4,094/9,000 =
(2 × 23 × 89)/(23 × 32 × 53) =
((2 × 23 × 89) ÷ 2) / ((23 × 32 × 53) ÷ 2) =
(23 × 89)/(22 × 32 × 53) =
2,047/4,500