2. Write the mixed repeating (recurring) decimal number as an improper fraction.
3.14 can be written as an improper fraction.
- The numerator is larger than or equal to the denominator.
Set up the first equation.
- Let y equal the decimal number:
y = 3.14
Set up the second equation.
- Number of decimal places repeating: 1
Multiply both sides of the first equation by 101 = 10
y = 3.14
10 × y = 10 × 3.14
10 × y = 31.4
Get the same number of decimal places as for y:
10 × y = 31.44
Note: 31.44 = 31.4
Subtract the first equation from the second one.
- Having the same number of decimal places ...
- The repeating pattern drops off by subtracting the two equations.
10 × y - y = 31.44 - 3.14 ⇒
(10 - 1) × y = 31.44 - 3.14 ⇒
We now have a new equation:
9 × y = 28.3
Solve for y in the new equation.
9 × y = 28.3 ⇒
y = 28.3/9
Let the result written as a fraction.
Now we can write the number as a fraction.
According to our first equation:
y = 3.14
According to our calculations:
y = 28.3/9
⇒ 3.14 = 28.3/9
Get rid of the decimal places in the fraction above.
- Multiply the top and the bottom number by 10.
- 1 followed by as many 0-s as the number of digits after the decimal point.
3.14 = (28.3 × 10)/(9 × 10)
3.14 = 283/90
3. Reduce (simplify) the fraction above:
283/90
to the lowest terms, to its simplest equivalent form, irreducible.
To reduce a fraction to the lowest terms divide the numerator and denominator by their greatest (highest) common factor (divisor), GCF.
Factor the numerator and denominator (prime factorization).
283 is a prime number, it cannot be factored into other prime factors
90 = 2 × 32 × 5
Calculate the greatest (highest) common factor (divisor), GCF.
Multiply all the common prime factors by the lowest exponents.
But, the numerator and the denominator have no common factors.
GCF (283; 2 × 32 × 5) = 1
The numerator and the denominator are coprime numbers (no common prime factors, GCF = 1). So, the fraction cannot be reduced (simplified): irreducible fraction.